Aball is thrown from a height of 123 feet with an initial downward velocity of 11/fts . the ball's height h (in feet) after t seconds is given by the following. =h−123−11t16t2 how long after the ball is thrown does it hit the ground?

2.45 seconds

Step-by-step explanation:

A ball is thrown from a height of  123 ft

Thus,

Initial velocity,

Acceleration due to gravity downwards,

The ball's height  h  (in feet) after  t  seconds is given by,

When ball hit the ground, h=0

Using quadratic formula,

Time can't be negative.

So, t=2.45 seconds

Hence, After 2.45 seconds ball hit the ground.

answer: 457.14

step-by-step explanation:

205 - 45 = 160

160 / .35 = 457.142857