Explain how you know that 7 over 12 is greater than 1 over 3 but less than 2 over 3?

For this problem, we can know that 1 over 3 is same as 4 over 12, and 2 over 3 is same as 8 over 12, so, that 7over 12 is greater than 1 over 3 but less than 2 over 3. hopes it can help you ~

38+105= 143, 39+104=143, and you will find then adding the numbers on opposite sides, moving inwards yields the answer 138 every time. because of this, you’re going to multiply 138 times the number of pairs, which is 34. therefore, 34*138= 4692(i’m sorry if it’s the wrong numbers, but it’s the right concept)