The length and width of a rectangle are consecutive odd integers. the perimeter is 64 meters. find the length and width.

width = 15 meters and length = 17 meters

Step-by-step explanation: To solve this problem, our first task is to set up variables for the width and length.

Since the width and length are consecutive odd integers, let's call the width of the rectangle X and the length of the rectangle X + 2.

To help set up our equation, I will provide a picture of the rectangle with the length and with labeled.

Since the perimeter of the rectangle is 64 meters, we can represent this with our equation which is as followed. Remember, perimeter is the distance around the rectangle.

X + X + (X + 2) + (X + 2) = 64

4x + 4 = 64   ← simplify on the left side

      -4    -4   ← subtract 4 from both sides

4x = 60

÷4   ÷4   ← divide both sides by 4

X = 15

width ⇒ X = 15

length ⇒ X + 2 = 17

Therefore, the width of the rectangle is 15 meters and the length of the rectangle is 17 meters.

p> q if you calculate p is100 q is 79

32/80  

91/140

the last one 54 doesn't go into 45. 54/100 ?

step-by-step explanation: