Which theorem or postulate proves that △abc and △def are similar?

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the two triangles are similar by the

SSS Similarity Theorem

Step-by-step explanation:

The answer is SSS Similarity Theorem because there is no angles labeled.

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From the given figure:

In triangle ABC

Side AB = 3 units, Side BC = 7 units and Side AC = 6 units.

In triangle DEF

Side DE = 18 units, Side EF = 42 units and Side DF = 36 units.

In triangle ABC and triangle DEF

⇒

SSS(Side-Side-Side) similarity theorem states that if three sides in one triangle are in same proportion to the corresponding sides of the other triangle, then these two triangles are similar

then, by SSS similarity theorem;

ΔABC ΔDEF

Therefore, the given two triangles are similar by SSS similarity theorem

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step-by-step explanation: