What is the fourth term of the sequence defined by a1 3xy 5 an y )an 1? (1) 12x 3 y 3 (3) 24x 4 y 2 (2) 24x 2 y 4 (4) 48x 5 y 1?

a1=3xy^ 5

an= (2x/ y )a(n-1)

then

a2=(2x/ y )a(1)= (2x/ y )* 3xy^ 5=6(x^ 2)(y^ 4)

a2=6(x^ 2)(y^ 4)

a3=(2x/ y )a(2)= (2x/ y )* 6(x^ 2)(y^ 4)=12(x^ 3)(y^ 3)

a3=12(x^ 3)(y^ 3)

a4=(2x/ y )a(3)=(2x/ y )*12(x^ 3)(y^ 3)=24(x^ 4)(y^ 2)

 The answer is a4=24(x^ 4)(y^ 2)

the multiples of 15 are 15, 30,45, 60, 75, 90, 105, 120, 135, 150, 165, 180, 195,   210, 225, 240, 255, 270, 285, 300, 315, 330, 345, 360, 375,   390, 405, 420, 435, 450, 465, 480, 495, 510, 525, 540, 555, 570, 585, 600, 615, 630, 645, 660, 675, 690, 705, 720, and 735.

the factors of 15 are 1, 3, 5, and 15.

hope that , fam!

-une, your fren : )