Apicture has a width that is 17 inches shorter than the length, and its total area is 480 square inches. find the dimensions of the picture. if x represents the length of the picture, which of the following equations is a model for the given word problem?

Length: 32in

Width: 15in

Step-by-step explanation:

Since the width of the picture is 17 inches shorter we can assume the picture is a rectangle. A rectangle's area is calculated using the following formula.

Where A is the area, L is the length, and W is the width. Since we are giving the area and are told that the width is 17 inches shorter than the length, we can plug that into the equation using the variables shown in the picture below and solve for x.

What we have here is a Quadratic Equation in which we will need the cuadratic formula as seen in the picture below to solve. We plus our equation into the Quadratic formula and solve it.

Since The width of the triangle is 17 less than the width we see that the width CANNOT be 15. So the only answer left is x = 32

This leaves us width the Length being 32 and the width being 15

I hope this answered your question. If you have any more questions feel free to ask away at .

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)