Two bicyclists started biking toward each other when they were 88 miles apart. three hours later there were 4 miles left between them. how fast was each bicyclist going if one of them was 4 mph slower than the other?

Alright, lets get started.

Suppose first bicyclist speed is = x mph

As given in question, second one is 4 mph slower than first, hence

Speed of second bicyclist is = (x-4) mph

They both travels 3 hrs so,

distance covered by first bicyclist :

distance covered by second bicyclist :

4 miles were still left after 3 hrs of driving.

It means they covered 88 - 4 = 84 miles together

Adding 12 in both sides

Dividing 6 in both sides

Means speed of first bicyclist = 16 mph

Speed of second bicyclist = mph

Hence speed of both bicyclist are 16 mph and 12 mph. : Answer

Hope it will help :)

5.5

step-by-step explanation:

x/3-10=8

x/3=18

x=48