Which is the equation of a line that passes through the points (-2,6) and (2,0)?

First we need to find the slope:

m = 0 - 6 / 2 + 2 = -6/4 = -3/2

So, the slope is -3/2.

Next we need to find the y-intercept:

0 = -3/2(2) + b

0 = -3 + b                                    Multiply.

3 = b                                            Add 3 to each side.

b = 3                                            Switch the equation around.

Now we can write the equation:

y = -3/2x + 3

y = -3/2x + 3

That is slope - intercept form.

There are two other ways you can write equations for lines.

There is also point slope form.

y - y1 = m(x - x1)

y - 6 = -3/2 (x + 2)

y - 6 = -3/2 (x + 2)

There is one more way we can write an equation for a line.

It is called standard form.

Ax + By = C

In standard form:

A, B, and C have to be integers. But, A has to be a positive integer.

y = -3/2x + 3

3/2x + y = 3

3x + 2y = 6

3x + 2y = 6

Now you only asked for one equation, but I gave you all 3.

So here they are again:

Final

Slope - Intercept Form: y = -3/2x + 3

Point Slope Form: y - 6 = -3/2 (x +2)

Standard Form: 3x + 2y = 6