10  points a model rocket is launched from the ground with an initial velocity of 160 ft/sec. how long will it take the rocket to reach its maximum height? show all work in the space provided.

This question would actually go under physics

Assuming that the model rocket goes straight up into the air and not at an angle, you can calculate for the maximum height by finding how long it takes for the velocity of the rocket to reach 0.

This can be calculated using the equation
t = (v sinx) /g
where t=time, v=velocity at zero seconds, x=angle of launch, g=gravity

Since we are assuming that the rocket flies straight up, the angle would be 90º, so sinx would be equal to 1.

That reduces are equation to 
t = v / g
g=9.81 m/s^-2

So we need to convert gravity to feet/second^-2 and divide 160 by g, 160 being the initial velocity.

g=9.81 m/s^-2 = 32.2 ft/s^-2

160/32.2 ≈ 4.97 seconds

first anwser choice.

step-by-step explanation:

the greater/less or equal to symbol (> or < with the line at the bottom) is a closed/filled in circle.

when multiplying or dividing by a negative on both sides you have to flip the inequality sign. this rule only applies to multiplying or dividing by a negative number in inequality equations. this rule is really important.

-5c + 2 _< _27

subtract from both sides by 2

-5c _< _ 27

divide both sides by -5

c _< _ 5.4

flip the inequality sign

c _> _5.4

the only possible answer that would match the simplified inequality is the first answer choice

Ibelieve the answer would be 7, 13, 23