Aright triangle has one leg that is 24 feet long and another that is 6 feet long what is the perimeter? a right triangle had a hypotenuse that is 15 inches long and one leg that is 9 inches long . what is the perimeter of the triangle?

In the first example we must calculate hypotenuse's length using pythagorean  theorem 
c^2 = a^2 + b^2 => c^2 = 24^2 + 6^2 = 576 + 36 = 612 => 
c = square root of 612 + 24.74 ft
perimeter P1 = a+b+c = 24+6+24.74= 54.74 ft
In the second example we must calculate second leg in the same manner
a^2 = c^2 - b^2 => a^2 = 15^2 - 9^2 = 225 - 81 = 144 =>
a = square root of 144 = 12 
perimeter P2= 15+9+12=36 ft
Good luck

Im sorry but what on