Acube and the net for the cube are shown.
what is the surface area of this cube?

a.
48 mm2

b.
64 mm2

c.
112 mm2

d.
384 mm2

do i do it on a graph?

step-by-step explanation:

the two may have that, even a breakdown is probably offered

place r′ so that qr′ is parallel to the tangent.

now we get that ∠r′py=∠pr′q, where y is on the tangent, on the opposite side of p from x.

also, because of the symmetry, ∠r′py=∠qpx.

finally, note that no matter where we place r, as long as it's on the correct arc, we have ∠prq=∠pr′q.

stringing all these equalities together, we end up with ∠prq=∠qpx.

this picture will show how its going to look like.

hope this by jack monhen