Find the sum of three consecutive odd integers where x is the greatest integer

X + (x − 2) + (x − 4) = ? ;  In which

x + x − 2 + x − 4 ; 

Combine the "like terms" ; 

  x + x + x = 3x ; 

  − 2 − 4  =  −6 ; 

So we have:  "3x  − 6" as the sum. ;

The sum of three consecutive odd integers, in which "x" is the greatest integer;  is:  "3x − 6" .

Note:  The three consecutive odd integers, from least to greatest, are:

"(x − 4)" , "(x − 2)" , and "x" .

The sum is:  "(3x  − 6)" .

Note:  "(3x  − 6)" factors into:  " 3(x −2)" .

Note that:  " (x − 2) " is the second integer.

So the sum total, which is:  "(3x  −  6)" ;  is 3 (three) times the value of the second integer; that is, "3 (x − 2)" .

Ithink not so sure but i tried it out and came out to be b