Brian has a bag that contains 14 red marbles and 12 yellow marbles. he selects a marble at random, and then, without replacing the first one, selects another marble at random. what is the probability that brian selects a red marble and then a yellow marble? round your answer to the nearest percent.

Answer=25%

14 red marbles
12 yellow marbles
26 total marbles

To solve this, we need to first find out the probability of the individual events...

The odds of selecting a red marble is 14 out of 26 total marbles: 14/26

The odds of selecting a yellow marble after the first marble was NOT replaced is 12 out of 25. (25 since the first marble wasn't replaced: 26-1=25) 12/25

Now lets multiple both probabilities together to solve for the chance of both happening consecutively

14/26*12/25= 168/650=84/325

84/325=0.25846153846= 25%