Afunction is represented by y = cos (2π/5)x - 1. determine the amplitude and period of the function. what is the equation of the midline? a) amplitude is 1; period is 5; y = 0 b) amplitude is 1; period is 2/5; y = 1 c) amplitude is 1; period is 5; y = −1 d) amplitude is 1; period is 2π; y = −1 ( explain how you get it)

Given that: y = cos(2pi/5)x -1

The general form of cos function is y = A cos(Bx+C) +D

So amplitude = A=1

Period = 2pi/B=2pi/(2pi/5)= 5

Phase shift = -C/B= 0

Vertical shift = D=-1

So the equation of the midline is y=-1

Sot he correct option is C.

r = 78539458390583095803458309458039485093485 or just 3

step-by-step explanation:

answer: y = -2.5x - 15

              (-6,0)

step-by-step explanation: