Need here : ) 5.02 1. solve the triangle. a = 50°, b = 13, c = 6 (2 points) a) a ≈ 10.2, c ≈ 26.3, b ≈ 103.7 b) a ≈ 14, c ≈ 26.3, b ≈ 103.7 c) no triangles possible d) a ≈ 14, c ≈ 30.3, b ≈ 99.7 2. solve the triangle. a = 12, b = 22, c = 95° (2 points) a) c ≈ 26, a ≈ 27.6°, b ≈ 57.4° b) c ≈ 26, a ≈ 54.4°, b ≈ 30.6° c) c ≈ 25.1, a ≈ 27.6°, b ≈ 57.4° d) c ≈ 25.1, a ≈ 31.6°, b ≈ 53.4° 3. find the area of the triangle with the given measurements. round the solution to the nearest hundredth if necessary. a = 50°, b = 30 ft, c = 14 ft (2 points) a) 160.87 ft2 b) 420 ft2 c) 134.99 ft2 d) 321.74 ft2 4. determine whether a triangle can be formed with the given side lengths. if so, use heron's formula to find the area of the triangle. (2 points) 240 121 263 a) 17,578.06 b) no triangle is formed. c) 17,592.16 d) 14,499.68 5. an airplane leaves an airport and flies due west 150 miles and then 170 miles in the direction s 49.17°w. how far is the plane from the airport (round to the nearest mile)? image of a triangle with legs of 150 and 170 miles and a hypotenuse with unknown length. the points on the ends of the hypotenuse are entitled airport and plane. the angle opposite the hypotenuse shows a 90 degree angle and an additional south west bearing of 49.17 degrees