Four interior angles of a pentagon measure 88,118,132,and 100. what is the measure of the fifth interior angle?

For any polygon:
Sum of Interior Angles = (Number of Sides -2) • 180 degrees
Since this is a pentagon, # of sides = 5
Sum of Interior Angles = (5 -2) • 180 degrees
Sum of Interior Angles = 3 * 180
Sum of Interior Angles = 540 degrees
Sum of the four angles
88 + 118 + 132 + 100 = 438
Therefore, angle 5 = 540 - 438 = 102 degrees.

Source:
http://www.1728.org/polygon.htm

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