Plz answer asap what are the answers to these problems 1.multiply. −37xy(−35x3y2) enter your answer in the box. 2.multiply. (3x+1)(x−1) express the answer in standard form. enter your answer in the box. 3.subtract. (x2+43x+10)−(−10x2−5x+10) express the answer in standard form. enter your answer in the box. 4.factor. 10m5+5m4−25m2 enter your answer in the box. 5.factor. 64x2−25y2 enter your answer in the box. 6.factor. 9x² + 66xy + 121y² enter your answer in the box. 7.factor. x2+14x+48 enter your answer in the box. 8.let f(x)=x2−13x+30 . what are the zeros of the function?

1. -37xy(-35x^3y^2), to multiply we multiply the the digits then similar unknowns  -37  ×-35 = 1295x(x^3) = x^4y(y^2) = y^3thus we get; 1295x^4y^32. multiply (3x+1)(x-1)      3x(x-1) +1(x-1)  = 3x²-3x +x-1    (combining the like terms)  = 3x²-2x-13. subtracting      (x²+43x+²-5x+10) we subtract the like terms  = x²+43x+10+10x²+5x-10    =11x²+48x+0  = 11x²+48x4. factorizing      10m^5+5m^4 - 25m²we get the factor of all the terms,    5m²(2m³+m²-5)5m² is the divisor of all terms  = 5m²(2m³+m²-5)5. factorizing;     64x²-25y²this the difference between two squares such that; (a²-b²) = (a-b)(a+b)therefore; 64x²-25y² = (8x-5y)(8x+5y)    = (8x-5y)(8x+5y)6. factorizing  9x²+66xy+121y²  p= 1089  s = 66numbers; = 33, 33thus; 9x²+33xy+33xy +121y²          3x(3x+11y)+11y(3x+11y)        = (3x+11y)(3x+11y)7. factorizing    x²+14x+48  p = 48  s= 14numbers; = 8, 6x²+6x+8x+48x(x+6)+8(x+6)=(x+8)(x+6)8.the zeros of the function; f(x)=x²-13x+30        x²-13x+30=0          p = 30          s = -13        numbers; -3,-10=  x²-3x-10x+30=0= x(x-3)-10(x-3) =0= (x-10)(x-3) =0therefore, x-10=0, x-3=0hence; x=10 and x=3