![\text{Var}[X]=E[X^2]-(E[X])^2 \\ E[X^2]=\sum x^2\Pr(X=x) \\ E[X] = \sum x\Pr(X=x)](/tpl/images/0395/5562/8b4f5.png)
.![E[X]=(1\times0.20)+(2\times0.30) + (3\times0.10) + (4\times 0.20)+(5\times0.05) ](/tpl/images/0395/5562/d4524.png)
, note we can get rid of the 0 because 0 times anything = 0![E[X]=(1^2\times0.20)+(2^2\times0.30) + (3^2\times0.10) + (4^2\times 0.20)+(5^2\times0.05) ](/tpl/images/0395/5562/7c125.png)
, note we can get rid of the 0 because 0 times anything = 0.![\text{SD}[X] = \sqrt{\text{Var}[X]}](/tpl/images/0395/5562/36699.png)
you find SD=[X]=1.46Give the standard deviation for the probability distribution. (round to two decimal places)
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Mathematics, 29.11.2019 02:31 oaaliyah505
Give the standard deviation for the probability distribution. (round to two decimal places)
Answers: 3
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