Prove that (160x^5)/(8x^2 (4x+5x+x^2))+14y-(7y+y^3 )-3y+20z/(13z-(3z+5z) )+15q-(4q*2q)+3q^2+[3jn+n(n^2 )]2+(160j^2)/(5j*8j) is equal to (20x^2)/9+20x+4y-y^3+15q-5q^2+6jn+2 n^3+8

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Answer: d. 39 cmin the diagram, the approximate length of the minor arc de is 39 centimetres.step-by-step explanation: the formula for the length of an arc in a circle is as displayed below.let the length of the minor arc de = xx = 2( pi )r × angle of sector / 360°from this, we will substitute the values given from the problem into the formula to obtain the length of the minor arc de.x = 2( pi )r × angle of sector / 360°r = radius = 25cmpi as an approximate value = 3.14angle of sector = 120°x = 2( 3.14 )( 25 ) × 120° / 360°x = 157 × 1 / 4x = 39.25x = 39 ( rounded to the nearest whole number as an approximate value )