An engineering school reports that 55% of its students were male (m), 40% of its students were between the ages of 18 and 20 (a), and that 25% were both male and between the ages of 18 and 20. what is the probability of a random student being female between the ages of 18 and 20? assume p(f) = p(not m).

Building and solving an equation, it is found that there is a 0.3333 = 33.33% probability of a random student being female between the ages of 18 and 20.

0.3333 = 33.33% probability of a random student being female between the ages of 18 and 20.

A similar problem is given at link

d

step-by-step explanation:

d

answer: all the values are within because it has a pattern that repeats from -6 to 4.

good luck!