Suppose a bag contains 4 white chips and 6 black chips. what is the probability of randomly choosing a white chip, not replacing it, and then randomly choosing another white chip? a.9/25 b.2/15 c.4/25 d.1/3

There are initially 4+6=10 chips in the bag, so the probability of the first chip drawn being white is:

4/10=2/5

Having drawn a white chip there are then 3 white chips left in the bag out of a total 3+6=9 chips. So the probability of the second chip also being white is:

3/9=1/3

So the probability of drawing two white chips is:

2/5x1/3=2/15

Pls mark brainliest

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages