![\bf sin(2x)-1=0\implies sin(2x)=1\implies sin^{-1}[sin(2x)]=sin^{-1}(1) \\\\\\ 2x=sin^{-1}(1)\implies 2x=\cfrac{\pi }{2}\implies x=\cfrac{\pi }{4}\textit{ which is }45^o](/tpl/images/0404/6401/e1d88.png)
How do you find the value of x in degrees.
sin 2x - 1 = 0...
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