The set of points (-3,4), (-1,1), (-3.-2), and (-5,1) identifies the vertices of a quadrilateral. which is the most specific describtion to tell which figure the points form?

It is an interesting problem.
Method 1: (simplest, can be done with pencil and paper)
Graph the points, and do a visual inspection.
See graph attached.

Method 2: by observations, without need to take square-roots (for distances)
We note that:
1. the x-coordinates of the first and third points are the same (-3), meaning that they lie on the same vertical line.
2. the y-coordinates of the second and fourth points are the same (1), that means that they lie on the same horizontal line.  So the diagonals are at right angles to each other, intersecting at P(-3,1).
These two observations tell us that the figure is either a square, rhombus, or a kite, or an arbitrary quadrilateral that has orthogonal diagonals.
3. AC=4-(-2)=6, BD=-1-(-5)=4, diagonals are not equal, so cannot be a square.
4.  PA=(4-1)=3, PB=(-3-(-1))=2, diagonals bisect each other, so it is a rhombus (not a kite).

A)26•2=52there are 2 sides with the same length116-52=64the other 2 side have to be half of 64 each64/2=32the width is 32b)make two sentences about these steps because your teacher knows how you write and explain things.

step-by-step explanation:

only stephen hawking would know.