4mm of ink a is added to 10 mm of ink b, forming a mixture of inks. ink a contains 10% blue pigment. ink b contains an unknown percentage of blue pigment. the mixture of the two inks contain 35% blue pigment. what percentage of blue pigment is in ink b? • 45% • 49% • 60% • 75%

35% are blue pigment, hence the mixture contains 4.9 mm of blue ink. Ink A contains 10%*4mm=0.4mm of blue ink. 4.5 mm of blue ink must have come from ink B. Thus ink B contains 4.5 mm of blue ink and is in total 10mm. 4.5/10=0.45 and this is the ratio of blue ink to total ink (in Ink B). If we transform it to percentages it is 45

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

the answer is b.)

< 1=< 2