Use the graph of the line to answer the questions. what is an equation of the line in point-slope form y+1=(1/3)(x+2)? how can the point-slope form be written in function notation?f(x)=(1/3)x-(1/3)

An equation of the line in point-slope form is y+ 1 = (1/3)(x+2)  (the third option)

The point-slope form can be written in function notation by f(x)=(1/3)x-(1/3)  (the second one)

Step-by-step explanation:

ED2020

An equation of the line in point-slope form is y+ 1 = (1/3)(x+2)  (the third option)

The point-slope form can be written in function notation by f(x)=(1/3)x-(1/3)  (the second one)

Step-by-step explanation:

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

i’ll just s take the points thxs