Is it possible to place 158 books on three shelves so that the first shelf has 8 fewer books than the second and 5 more books than the third shelf? plz halp

We are given 158 books to place them on three different shelves like A, B, and C.

It says that shelf A has eight fewer books than shelf B and five more books than shelf C.

Mathematically, it can be written as (A = B - 8) and (A = C + 5).

Or we can write it as (B = A + 8) and (C = A - 5).

If we consider there are 'x' books in shelf A, then shelf B would have 'x+8' books and shelf C would have 'x-5' books.

We know that Total books are 158, so its sum must be equal to total books.

A + B + C = 158

x + (x+8) + (x-5) = 158

3x + 3 = 158

3x + 3 - 3 = 158 - 3

3x = 155

x = 51.667 books

But 'x' must be an integer value because number of books can not be a decimal form.

Hence, this arrangement is "NOT possible" for this question.

not only in mathematics, scientific proof also are required in the other field of science. also maths proofs are of particular structure, containing steps and logics. so proving is like doing science, it is science. that's why it is important to prove. 

an inaccurate proof leads to errors, or stating results that are not accurate.  which wil mess the probelm up you dont want this

step-by-step explanation:

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