Three sets of a sum of a number and four are added to the sum of 7 times the same number and 13

Let
x> a number

we know that
three sets of a sum of a number and four> 3(x+4)
the sum of 7 times the same number and 13> 7x+13

therefore

(Three sets of a sum of a number and four) are added (to the sum of 7 times the same number and 13) > [3(x+4)] + [7x+3]

[3(x+4)] + [7x+3]> [3x+12] + [7x+3]=10x+15

the answer is 10x+15

The answer is the numbers between =5 and 5

Use photo math it