Hurryline segment ct contains the point c(−2, 5) and a midpoint at a(1, −3). what is the location of endpoint t? t(4, −11) t(3, −8) t(5, −1) t(−0.5, 1)

Point A is the midpoint of CT which means the ratio of CA:CT would be 1:2.
To find CT, you need to find the distance of CA then applies 2 times of the distance to the point C

Xca= Xa-Xc= 1- (-2)= 3
Yca= Ya- Yc= -3 -5= -8

Xt= Xc + 2* Xca= -2 + 2*3= 4
Yt= Yc + 2* Yca= 5 + 2*-8= -11
T(Xt, Yt)= T(4, -11)

The coordinate for point T would be (4, -11)