Auniversity football stadium has 1/6 of its students' seats in the end zones. if tickets are randomly selected and mailed to students, what is the probability that a certain student would get end zone seats at all 5 home games?

1/7,776

Step-by-step explanation:

the odds of getting an end zone seat once is 1/6 so you multiply that by itself 5 times to get your answer.

1/6 x 1/6 x 1/6 x 1/6 x 1/6 x 1/6 = (1/6)^5 = 1/7,776.

i think it would be c

mark brainliest if im right

step-by-step explanation: