Find the image of o (0,0) after two reflections, first across l1 and then across l2: l1: y = 2 l2: x = -3

Some standard rules:
reflection about horizontal line y=k
reflection about vertical line x=h

So for O(0,0), h=-3, k=2
First reflection about L1: y=2
(x,y)->(x, -y+2(k)) =>
O(0,0)->O'(0,-0+2(2) = O'(0,4)
Second reflection about L2: x=-3
(x,y)->(-x+2h,y) =>
O'(0,4)->O''(0+2(-3),4) = O"(-6,4)

after both reflections, the position of image is O"(-6,4)

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