Acombination lock has a code consisting of 3 numbers, each of which can be 0 to 39, with numbers repeated. jillian says that there are only 120 possible codes. is jillian correct? if not, explain her error.

Jillian is not correct

Jillian has summed up the possible number of codes for each digit instead of multiplying it

Step-by-step explanation:

The lock has a code that consists of 3 number

It is given that the number in the lock code can be used between to

Thus, out of total set of numbers (i.e ), the numbers can be repeated.

This means for all three code numbers the opportunity of choosing a number is same  i.e. between  

Now, the first digit of the code can be any number between  

Like wise the second and third  digit of the code can be any number between  

Thus. the possible number of codes with repetition allowed are

Hence, Jillian is not correct

Jillian has summed up the possible number of codes for each digit instead of multiplying it

a net is a diagram that shows a “flattened” view of a solid. in a net, each face and base is shown with all of its dimensions. a net can also serve as a pattern to build a three-dimensional solid.

a pyramid is a three-dimensional object with a base that is a polygon and triangular faces that meet at one vertex.

" the net of a triangular pyramid consists of four triangles. the base here we are given of the pyramid is a equilateral   triangle, and the lateral faces are also triangles "

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)