How many different possible outcomes are there when jillana spins the spinner below and then flips the coin? the spinner is from 1-6.

There are total 12 outcomes

Step-by-step explanation:

The number of outcomes in spinning a spinner is 6 (getting a number from 1 to 6)

The number of outcomes in flipping a coin=2  (head or tail)

Hence, total 12 outcomes are possible which are:

(1,H) (2,H) (3,H) (4,H) (5,H) (6,H)

(1,T)  (2,T)  (3,T) (4,T)  (5,T)  (6,T)

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15