2) a cake in the shape of a circus tent is used as a centerpiece at a celebration. the cake consists of a cylinder and a cone. the cylinder has a diameter of 12 inches and a height of 14 inches. the cone has a height of 6 inches. what is the volume of the cake? round your answer to the nearest tenth of a cubic inch. use 3.14 to approximate pi. show your work
plz , so confused

You have:
 
 - The diameter of the cylinder is 12 inches and its height is 14 inches.
 -The height of the cone is 6 inches.
 
 So, you must apply the formula for calculate the volume of the cylinder a the formula for calculate the volume of a cone. 
 
 V1=πr²h
   
 V1 is the volume of the cylinder.
 r is the radius.
 h is the height (h=14 inches)
 
 The problem gives you the diameter, but you need the radius, so you have:
 
 r=D/2
 r=12 inches/2
 r=6 inches
 
 When you substitute the values into the formula, you obtain:
 
 V1==πr²h
 V1=(3.14)(6 inches)²(14 inches)
 V1=1582.56 inches³
 
 The volume of the cone is:
 
 V2=(πr²h)/3
 
 V2 is the volume of the cone.
 r is the radius (r=6 inches)
 h is the height of the cone (h=6 inches).
 
 Then, you have:
 
 V2=(πr²h)/3
 V2=(3.14)(6 inches)²(6 inches)/3
 V2=226.08 inches³
 
 Therefore, the volume of the cake (Vt) is:
 
 Vt=V1+V2
 Vt=1582.56 inches³+226.08 inches³
 Vt=1808.6 inches³