Write a quadratic function f whose zeros are 3 and 8

The standard form of a quadratic equation is: ax²+bx+c=0, and it is represented with a polynomial of degree 2, that's why it is also called "Equation of degree 2".
 
 1. So, if 3 and 8 are zeros of the quadratic function, then they are factors of it. Therefore, you have:
 
 (x+3)(x+8)=0
 
 2. When you write it in the standard form, you have:
 
 x²+11x+24=0
 
 a=1
 b=11
 c=24

Iam not sure , but probably 750 or 7.5