In a geometric sequence, a7=14 and r= -1/2. what is the 10th term of the sequence? • -3.50 • -1.75 • 1.75 • 3.50

We know that
in geometric sequence the formula is
an=a1*r^(n-1)
where
an>  is the nth term
a1 > is the first term
n > is the number of the term
r > is the common ratio
a7=14
r=(-1/2)

Step 1
find the a1 term
a7=a1*r^(7-1)> 14=a1*(-1/2)^(6)
a1=14/[(-1/2)^(6)]> a1=896

Step 2
find the a10 term
a10=a1*r^(10-1)> 896*(-1/2)^9=-1.75

the answer is a10=-1.75

Dwould be the answer