An expression is shown below: 3x3y + 15xy − 9x2y − 45ypart a: rewrite the expression so that the gcf is factored completely. show the steps of your work. part b: rewrite the expression completely factored. show the steps of your work.

A)  the gcf of the polynomial is 3y.  every monomial in the polynomial is divisible by 3, and each has an y.  factoring this out we have: 3y(x³ + 5x - 3x² - 15)b)  we continue factoring by grouping what we have in parentheses.  the first two terms both have an x, so we factor it out: 3y(x(x² + 5) - 3x² - 15)the last two terms are divisible by -3, so we factor it out: 3y(x(x²+5) - 3(x²+5))now we see a common factor inside parentheses we can factor out: 3y(x²+5)(x-3)