2x + 3y = 18 3x -4y > 16. give the domain and range, slope, and y-intercept for each line. graph each equation above on the graph below and show all work. give the domain and range, slope, and y-intercept for each line. explain in detail how you got each answer. 2x + 3y = 18 3x -4y > 16 slope-intercept form: slope-intercept form: domain: domain: range: range: slope: slope: y-intercept: y-intercept:

We have that
2x + 3y = 18
3x -4y > 16

Part A)
2x + 3y = 18 -------> 3y=[18-2x]---------> y=6-(2/3)x  (Slope-Intercept Form)

using a graph tool
see the attached figure

the domain is the interval  (-∞,∞)--------> ( all real numbers)
Domain of a function f (x) is the set of all the values of x for which the function is defined

the range is the interval     (-∞,∞)--------> ( all real numbers)
Range of the function f(x) is the set of all the values that f(x) takes

Slope-Intercept Form------------>  y=6-(2/3)x---------> [y=mx+b]
where
m------> is the slope------------> m=-2/3
Slope=-2/3
Y-intercept is the point for y=0
y=6-(2/3)x-------------> 0=6-(2/3)x--------> x=9
Y-intercept is the point (9,0)

Part B)
3x -4y > 16----------> -4y > 16-3x-----> y < -4+(3/4)x   (Slope-Intercept Form)
using a graph tool
see the attached figure

the domain is the interval  (-∞,∞)--------> ( all real numbers)
Domain of a function f (x) is the set of all the values for which the function is defined

the range is the interval     (-∞,∞)--------> ( all real numbers)
Range of the function f(x) is the set of all the values that f(x) takes

Slope-Intercept Form------------>   y = -4+(3/4)x---------> [y=mx+b]
where
m------> is the slope------------> m=3/4
Slope=3/4
Y-intercept is the point for y=0
y = -4+(3/4)x------------->0= -4+(3/4)x-----> 4=(3/4)x----> 16/3 = x----> x=16/3
Y-intercept is the point (5.33,0)