Mathematics, 25.09.2019 03:00 lathwkuster

Find the area of the shaded portion in the square (assuming the center point of each arc is the corresponding central point of the line and the arcs intersect at the center point of the circle)

Find the area of the shaded portion in the square (assuming the center point of each arc is the corr

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Answer from: igotdiss2178

The answer is 2. hope it helps!

Step-by-step explanation:

Answer from: zekrader18

The area of the shaded portion is $(\pi-2)~\textup{sq. units}.$

Correct option is 2.

Step-by-step explanation: We are given to find the area of the shaded portion in the figure.

Since, the centre point of each arc is the corresponding central point of the line and the arcs intersect at the centre point of the circle,

so let us divide the figure into four equal parts, one of them is square ABCD as shown in the attached figure.

The area of the square ABCD will be

$A_{ABCD}=\left(\dfrac{1}{2}\times 2\right)^2\\\\\\\Rightarrow A_{ABCD}=1~\textup{sq. units}.$

Now, area of the shaded portion inside the square ABCD will be

$A_s=2\times \textup{area of the quarter circle with radius 1 unit}}-\textup{area of square ABCD}\\\\\Rightarrow A_s=2\times \left(\pi\times \left(\dfrac{1}{2}\right)^2\right)-A_{ABCD}\\\\\\\Rightarrow A_s=2\times\left(\dfrac{\pi}{4}\right)-1\\\\\\\Rightarrow A_s=\left(\dfrac{\pi}{2}-1\right)~\textup{sq. units}.$

Since all the four squares are identical in the attached figure, so the required area of the total shaded portion in the figure is

$A=2\times\left(\dfrac{\pi}{2}\right)\\\\\\\Rightarrow A=(\pi-2)~\textup{sq. units}.$

Thus, the area of the shaded portion is $(\pi-2)~\textup{sq. units}.$

The correct option is 2.

Find the area of the shaded portion in the square (assuming the center point of each arc is the corr

Answer from: Quest

see below

step-by-step explanation:

7. there are 10 data points in the set. the middle point is between 5 and 6. the middle point in the top half is 8 and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term point 8 = 100 point 3 = 88

iqr = 100-88 = 12

final point 8 = 93 point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6. b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical . there is an outlier for the males that skews the data

5. the iqr is a better measure of spread for the movies and basketball games. since the basketball game has an outlier, we do not want to use standard deviation for measurement.

3. the exam median is much higher than the class median. the median line is farther to the right on the exams

2. there is no way to tell what the means are from the box and whisker plots.

Answer from: Quest

Answer d; a supplementary angle = 180°, so if that angle = 150°, y would = 30°.
In the diagram below, ab is parallel to cd. what is the value y? a.150b.50c.60d.30

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