Six rectangles each with a common base width of 22 have lengths of 1,4,9,16,251,4,9,16,25, and 3636. what is the sum of the areas of the six rectangles?

The area of the rectangle is the product of the length and the width of the quadrilateral. Hence, the sum of the areas is equal to  $2*1+2*4+2*9+2*16+2*25+2*36$. This is simply equal to $2*(1+4+9+16+25+36)$, which is equal to $2*91$, which is equal to our final answer of 182.