Mathematics, 18.08.2019 10:00 kathiewallentin1767

Any number that is divisible by 3 is also divisible by 9.
find a counterexample to show that the conjecture is false.
18
27
45
48

Answers: 1

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$48\ is\ divisible\ by\ 3\ but\ isn't\ divisible\ by\ 9:\\\\48:3=16\\\\48:9=5\frac{3}{9}=5\frac{1}{3}\\\\Other\ examples:\\\\51:3=17;\ 51:9=5\frac{2}{3}\\\\6:3=2;\ 6:9=\frac{2}{3}\\\vdots$

Answer from: cloudFF

For a number to be divisible by 9 the sum of the digits is also divisible by 9.
For the examples given 48 (4+8 = 12) (1 + 2 = 3) therefore 48 is not divisible by 9 as the sum of the digits is 3.

For a number to e divisible by 3 the sum of the digits is also divisible by 3. (eg 48 (4+8 = 12), (1 + 2 = 3) therefore 48 is divisible by 3

Answer from: Quest

step-by-step explanation:

try remembering the steps

Answer from: Quest

step-by-step explanation:

i found the life tables for the year 2012.

life table of males at age 30. probability of dying between ages x and x+1

total population:

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old.

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497

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Any number that is divisible by 3 is also divisible by 9.
find a counterexample to show that th...

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