Curtis build a dog house with base shaped like a cube and a roof shaped like a pyramid. the cube has an edge lenght of 3 1/2 feet. the height of the pyramid is 5 feet. find the volume of the doghouse rounded to the nearest tenth.

 The volume of the cube is:
 V1 = L ^ 3
 Where,
 L: length of the sides of the cube.
 Substituting we have:
 V1 = (3 + 1/2) ^ 3
 V1 = 42,875 feet ^ 3
 The volume of the pyramid is:
 V2 = ((Ab) * (h)) / (3)
 Where,
 Ab: base area
 h: height
 Substituting we have:
 V2 = (((3 1/2) * (3 1/2)) * (5)) / (3)
 V2 = 20.41666667 feet ^ 3
 The volume of the house is the sum of both volumes:
 V1 + V2 = 42,875 feet ^ 3 + 20.41666667 feet ^ 3
 V1 + V2 = 63.29166667 feet ^ 3
 Nearest tenth:
 V1 + V2 = 63.3 feet ^ 3
 
 The volume of the doghouse rounded to the nearest tenth is:
 V1 + V2 = 63.3 feet ^ 3

If you make it a little more clear i can answer it