The areas of two similar octagons are 112 in.² and 63 in.². what is the ratio (larger to smaller) of their perimeters? 16/3 4/9 16/9 4/3,

When the figures are similar, we have by definition:
 For the area:
 A1 = (k ^ 2) * A2
 For the perimeter
 P1 = k * P2
 Note: The factor k is the same in both cases
 Where,
 k = growth factor (k> 1) or reduction (k <1)
 Substituting values we have:
 12 = (k ^ 2) * 63
 Let's clear k:
 k = root (112/63)
 k = 4/3
  
 The ratio (larger to smaller) of their perimeters is:
 k = 4/3

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