Find z such that 6.8% of the standard normal curve lies to the left of z. (round your answer to two decimal places.)

The correct answer is z=-1.49.

Explanation:

We use a z-table to find the answer.  Instead of looking at the values to the left of the table, which show us the z-score, we look in the center to find the area to the left of the z-score in the curve.  We know we want 6.8% of the data to fall to the left of the score; 6.8% = 6.8/100 = 0.068.  In the center cells of the table, the z-score that is closest to this score is -1.49.

The correct answer is c

The variables should add up to equal 1