What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (2, 5)? y + 5 = x + 2 y − 2 = x − 5 y − 5 = −(x − 2) y + 2 = −(x + 5)

We are given point (2,5).

We need to find the equation of line perpendicular to the given line and passes through the point (2, 5).

We know point-slope form :

y-y1 = m(x-x1).

Plugging values of (x1,y1) = (2,5) in above slope-intercept form, we get

y - 5 = m(x-2).

Which matches 3rd option y − 5 = −(x − 2).

y > 1/3x

y < = -x + 4

hope this : )

range is infinite on both x and y axis positive and negative

step-by-step explanation: