Tickets to a play cost $5 at the door and $4 in advance. the theater club wants to raise at least $400 from the play. write and graph an inequality for the number of tickets the theater club needs to sell. if the club sells 40 tickets in advance, how many tickets do they need to sell at the door to reach their goal?
and show how to do this work. you!

Step-by-step explanation:

Let us notice that the questioner had put the words "at least" in their problem; so this would be an inequality problem.

Let us say x represents the number of tickets sold at the door and y is the number of tickets sold in advance.

If this is so, your problem should be;

5x+4(40)≥400

1. Distribution; 5x+160≥400

2. Subtract 160 from both sides; 5x+160-160≥400-160

3. you are left with; 5x≥240

4. divide 5 from both sides; 5x/5≥240/5

5. you are left with; x ≥ 48

Meaning; they need to sell 48 or more tickets at the door to reach their goal of $400.

two data sets with the same median will not have the same varaibility

step-by-step explanation:

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;