Mathematics, 29.01.2020 04:06 LillyPrince

1. which function is shown on the graph?
f(x)=1/2cosx
f(x)=−1/2sinx
f(x)=−1/2cosx
f(x)=1/2sinx

2. (picture)

3.(picture)

4.(which equation represents the function on the graph?

5. what is the period of the funtion f(x)=cos2x?

1. which function is shown on the graph? f(x)=1/2cosx f(x)=−1/2sinx f(x)=−1/2cosx

Answers: 3

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Answers

Answer from: EmilyQuinn3053

The reasons and responses to the graphs in the question are as follows:

Graph 1.

The amplitude of the first graph is (1/2) which is the height from the midline to the peakThe value of the function at x = 0 is -(1/2), where sin(0) = 0, therefore, the function is a cosine functionThe period of the graph is 2·π, which is the period of the parent cosine functionTherefore, the correct option is $f(x) = -\dfrac{1}{2} \cdot cos(x)$

Graph 2: Please find attached the graph of the function g(x) = 2×cos(x)

Graph 3: The frequency of a sinusoidal function is given as follows;

$Frequency = \dfrac{2 \cdot \pi }{Period}$

The period of the graph = π

Therefore;

$The \ frequency = \dfrac{2 \cdot \pi }{\pi} = 2$

The frequency of the sinusoidal graph is 2

Graph 4. Required:

To find the equation that represents the function of the graph

Solution;

The period of the function, T = π

The graph of the function has a maximum at x = 0, therefore, the graph is similar to a cosine function, y = cos(B·x)

Where;

B = 2·π/T

Therefore;

B = 2·π/π = 2

Therefore;

The equation that represent the function in the graph is f(x) = cos(2·x)

Question 5. The given function is f(x) = cos(2·x)

The frequency factor in the given function, B = 2

The period, T = 2·π/B

Therefore, T = 2·π/2 = π

The period of the function, f(x) = cos(2·x), is 2

Learn more about sinusoidal function here:

link

1. which function is shown on the graph? f(x)=1/2cosx f(x)=−1/2sinx f(x)=−1/2cosx f(x)=1/2sinx 2. (

Answer from: paolaviviana

Problem 1

choice C) f(x) = (-1/2)cos(x)

We can rule out anything with sine in it since the graph does not go through the origin. We can rule out choice A as well since plugging x = 0 into f(x) leads to a positive result, when instead we want a negative value. So the only thing left is choice C

======================================================
Problem 2

See the attached image

Point A is approximately (1.57, 0) which is exactly (pi/2, 0)
Point B is approximately (3.14, -2) which is exactly (pi, -2)

======================================================
Problem 3

1/pi

Period = pi since the graph repeats itself every pi units
Frequency = 1/Period
Frequency = 1/pi

======================================================
Problem 4

Choice A) f(x) = cos(2x)

This is a cosine function as it doesn't go through the origin. The period is T = pi, so b = 2pi/T = 2pi/pi = 2 is the coefficient of the inner x term. Therefore the function is f(x) = cos(2x)

======================================================

1. which function is shown on the graph? f(x)=1/2cosx f(x)=−1/2sinx f(x)=−1/2cosx f(x)=1/2sinx 2. (

Answer from: Quest

its 4 because 2 times 2 is 4, if you double the number two you get four

Answer from: Quest

answer 1 : option "c"

answer 2 : option "d"

answer 3 : option "b"

answer 4 : option "d"

answer 5 : option "b"

answer 6 : option "a"

answer 7 : option "c"

answer 8 : option "d"

answer 9 : option "c"

answer 10 : option "d"

answer 11 : option "c"

answer 12 option "b"

answer 13 option "c"

answer 14 option "c"

answer 15 option "d"

answer 16 option "a"

answer 17 option "b"

answer 18 option "c"

answer 19 option "a"

answer 20 option "a"

answer 21 option "c"

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1. which function is shown on the graph?
f(x)=1/2cosx
f(x)=−1/2sinx
f(x)=−1/2cosx...

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