Rodney bought a 25-pound bag of dog food. his dog ate 10 2/5 pounds of the food in the first month and 10 4/5 pounds in the second month. how much dog food, in pounds, was remaining in the bag at the end of the two months?

pounds of food

Step-by-step explanation:

We have been given that Rodney bought a 25-pound bag of dog food. His dog ate pounds of the food in the first month and pounds in the second month.  

Let us find the amount of dog-food eaten by dog in two months.

Now we will subtract amount of food eaten by dog from the amount of food initially to find the remaining amount of dog food.

Therefore, pounds of food was remaining in the bag at the end of the two months.

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

step-by-step explanation:

there's the chart