Apool is being drained at a constant rate. the amount of water is a function of the number of minutes the pool has been draining, as shown in the table. write an equation in slope-intercept form that represents the function. then find the water in the pool after two and a half hours.
time (mi)
volumne (gal) 4962--4754--3974

Using the first two values in the table, we can first find the slope to write an equation of a line, so we have

[4754 - 4962 ] / [20 - 12 ] = -26

So we have

y - 4754 = -26(x - 20)  

y - 4754  = -26x + 520

y = -26x + 5274

Let's confirm that the amount after 50 minutes is correct

y = -26(50) + 5274  = 3974

So after  2 + 1/2 hrs  (150 min) we have

y = -26(150) + 5274  = 1374 gallons

Step-by-step explanation:

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step-by-step explanation: