What value of  b  will cause the system to have an infinite number of solutions? y  = 6x  –  b         –3x  +  y  =  –3

the correct question is

  what value of b will cause the system to have an infinite number of solutions?

for

y  = 6x  –  b    and  -3x+(1/2)y=-3

  we have that

y  = 6x  –  b    > equation 1

-3x+(1/2)y=->   -6x+y=- > -2x+y=- > y=6x-6

y=6x-> equation 2

  we know that

for the system to have an infinite number of solution, equation 1  must be equal to equation 2

so

6x  –  b=6x-> 6x-6x=b-> b=6

  the answer is b=(6)

the difference between a number and 5 is -2.

step-by-step explanation:

notice that the equation you are given has -2 (negative 2) on the right side, not 2. when you subtract 5 from a number n, you are finding the difference between the number and 5.

the difference between a number and 5 is -2.