What are the zeros of the quadratic function f(x) = 2x2 + 8x – 3? x = –2 – and x = –2 + x = –2 – and x = –2 + x = 2 – and x = 2 + x = 2 – and x = 2 +

The answer is A for anyone that doesn't understand the other answer.

The given quadratic function is:



The zeros of the quadratic functions also known as its roots can be found using the quadratic formula.

According to the quadratic formula:


here,
b = coefficient of x-term
a = coefficient of x²-term
c = costant term

For given function:
a = 2
b = 8
c = - 3

Using these values in the formula, we get:



Thus, these values of x are the zeros of the given quadratic function f(x)=2x²+8x-3

I’m going to infer you said parallel.solve for yy= -1/2x+7/4lines that are parallel have the same slope, different y intercept.so we know m is -1/2then from there solve for y intercept.

300b(x) is graphed by the functio